<?xml version="1.0" encoding="UTF-8"?>
<feed xmlns="http://www.w3.org/2005/Atom" xml:lang="en-gb">
	<link rel="self" type="application/atom+xml" href="https://forums.obdev.at/app.php/feed/topic/1874" />

	<title>Objective Development Forums</title>
	
	<link href="https://forums.obdev.at/index.php" />
	<updated>2008-11-06T19:41:26+02:00</updated>

	<author><name><![CDATA[Objective Development Forums]]></name></author>
	<id>https://forums.obdev.at/app.php/feed/topic/1874</id>

		<entry>
		<author><name><![CDATA[morrog]]></name></author>
		<updated>2008-11-06T19:41:26+02:00</updated>

		<published>2008-11-06T19:41:26+02:00</published>
		<id>https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6616#p6616</id>
		<link href="https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6616#p6616"/>
		<title type="html"><![CDATA[Diodes in place of 3.3V LDR?]]></title>

		
		<content type="html" xml:base="https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6616#p6616"><![CDATA[
I'm still pretty new to electronics, so I had not known about the forward voltage on diodes. Thank you for the explanation. Very helpful <img class="smilies" src="./../../../images/smilies/icon_smile.gif" alt=":)" title="Smile" /><p>Statistics: Posted by <a href="https://forums.obdev.at/memberlist.php?mode=viewprofile&amp;u=1473">morrog</a> — Thu Nov 06, 2008 7:41 pm</p><hr />
]]></content>
	</entry>
		<entry>
		<author><name><![CDATA[henni]]></name></author>
		<updated>2008-11-06T11:54:57+02:00</updated>

		<published>2008-11-06T11:54:57+02:00</published>
		<id>https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6615#p6615</id>
		<link href="https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6615#p6615"/>
		<title type="html"><![CDATA[Re: Diodes in place of 3.3V LDR?]]></title>

		
		<content type="html" xml:base="https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6615#p6615"><![CDATA[
<blockquote><div><cite>morrog wrote:</cite>...two diodes in place of a 5V to 3.3V regulator. I can't image how two diodes are supposed to drop the voltage down from 5V to 3.3V.</div></blockquote><br /><br />A silicon diode has a forward voltage (Flussspannung) of about 0.7 V. Two diodes will drop the 5V down to 5V - (2* 0.7V) = 3.6V, which is sufficient low voltage for the USB lines. An extra advantage is that diodes have no quiescent current, therefore, standard conform USB sleep mode (less than 500 µA current) is easiest with these two diodes.<p>Statistics: Posted by <a href="https://forums.obdev.at/memberlist.php?mode=viewprofile&amp;u=1319">henni</a> — Thu Nov 06, 2008 11:54 am</p><hr />
]]></content>
	</entry>
		<entry>
		<author><name><![CDATA[morrog]]></name></author>
		<updated>2008-11-06T08:24:08+02:00</updated>

		<published>2008-11-06T08:24:08+02:00</published>
		<id>https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6613#p6613</id>
		<link href="https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6613#p6613"/>
		<title type="html"><![CDATA[Diodes in place of 3.3V LDR?]]></title>

		
		<content type="html" xml:base="https://forums.obdev.at/viewtopic.php?t=1874&amp;p=6613#p6613"><![CDATA[
On the homepage for AVR USB, the schematic shows two diodes in place of a 5V to 3.3V regulator. Would that really work? I can't image how two diodes are supposed to drop the voltage down from 5V to 3.3V.<br /><br />Thank you.<p>Statistics: Posted by <a href="https://forums.obdev.at/memberlist.php?mode=viewprofile&amp;u=1473">morrog</a> — Thu Nov 06, 2008 8:24 am</p><hr />
]]></content>
	</entry>
	</feed>
